Skip to content
Programmingoneonone
Programmingoneonone

LEARN EVERYTHING ABOUT PROGRAMMING

  • Home
  • CS Subjects
    • IoT ? Internet of Things
    • Digital Communication
    • Human Values
  • Programming Tutorials
    • C Programming
    • Data structures and Algorithms
    • 100+ Java Programs
    • 100+ C Programs
  • HackerRank Solutions
    • HackerRank Algorithms Solutions
    • HackerRank C problems solutions
    • HackerRank C++ problems solutions
    • HackerRank Java problems solutions
    • HackerRank Python problems solutions
Programmingoneonone

LEARN EVERYTHING ABOUT PROGRAMMING

HackerEarth Beautiful pair of nodes problem solution

YASH PAL, 31 July 2024
In this HackerEarth Beautiful pair of nodes problem solution You are given a rooted tree having n nodes, rooted at node 1. Every node i has two values associated with itself , A[i] and B[i]. In this tree you have to count total pairs of nodes which are beautiful. A pair of nodes i , j is beautiful if i is ancestor of node j and A[i] < A[j] and B[i] < B[j].
Node i is called an ancestor of some node j, if node i is the parent of node j, or it is the ancestor of parent of node j. The root of a tree has no ancestors.
HackerEarth Beautiful pair of nodes problem solution

Topics we are covering

Toggle
  • HackerEarth Beautiful pair of nodes problem solution.
    • Second solution

HackerEarth Beautiful pair of nodes problem solution.

#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
#include <bits/stdc++.h>
#define LL long long int
using namespace __gnu_pbds;
using namespace std;

typedef
tree<
pair<int,int>,
null_type,
less<pair<int,int>>,
rb_tree_tag,
tree_order_statistics_node_update>
ordered_set;

vector<int> graph[2000001];
set<int> temp;
bool visit[2000001];
int idx = 0;
int a[2000001];
int b[2000001];
LL final_ans = 0;


unordered_map<int,int> m;


ordered_set BIT[200001];

void remove(int pos, int val,int node)
{
while(pos <= 200000)
{
BIT[pos].erase(make_pair(val , node));
pos += (pos & (-pos));
}
}

void add(int pos,int val,int node)
{
while(pos <= 200000)
{
BIT[pos].insert(make_pair(val , node));
pos += (pos & (-pos));
}
}

void query(int pos,int val)
{

while(pos > 0)
{
final_ans = final_ans + (LL)(BIT[pos].order_of_key(make_pair(val , 0)));
pos -= (pos & (-pos));
}
}

void dfs(int node)
{
++idx;
query(m[a[node]]-1 , m[b[node]]);
add(m[a[node]] , m[b[node]] , node);
visit[node] = 1;
for(int i = 0 ; i < graph[node].size() ; i++)
{
if(visit[graph[node][i]] == 0)
{
visit[graph[node][i]] = 1;
dfs(graph[node][i]);
}
}
remove(m[a[node]] , m[b[node]] , node);
--idx;
}

#define s(x) scanf("%d",&x)

int main()
{
ios_base::sync_with_stdio(0);
int n;
s(n);
for(int i = 1 ; i <= n - 1 ; i++)
{
int u , v;
s(u);
s(v);
graph[u].push_back(v);
graph[v].push_back(u);
}
for(int i = 1 ; i <= n ; i++)
{
s(a[i]);
temp.insert(a[i]);
}
for(int i = 1 ; i <= n ; i++)
{
s(b[i]);
temp.insert(b[i]);
}
int idxs = 0;
for(int i : temp)
{
m[i] = ++idxs;
}
temp.clear();
dfs(1);
printf("%lld",final_ans);
}

Second solution

import java.io.*;
import java.util.*;
import java.math.*;
import java.util.concurrent.*;

public final class beautiful_nodes
{
static BufferedReader br=new BufferedReader(new InputStreamReader(System.in));
static FastScanner sc=new FastScanner(br);
static PrintWriter out=new PrintWriter(System.out);
static Random rnd=new Random();
static int[] x,y,cnt;
static Pair[] a;
static int[][] al;
static int time=-1;
static int[] c,tin,tout,arr;
static int maxn=(int)(1e5+5);
static int[][] bit;
static int block=3;
static int[] start,end,idx;

static void dfs(int u,int p)
{
tin[u]=++time;arr[time]=-1;

for(int x:al[u])
{
if(x!=p)
{
dfs(x,u);
}
}

tout[u]=time;
}

static void shuffle(int[] a)
{
for(int i=0;i<a.length;i++)
{
int next=rnd.nextInt(a.length);

int temp=a[i];a[i]=a[next];a[next]=temp;
}
}

static void update(int curr_idx,int val)
{
update(idx[curr_idx],val,1);

arr[curr_idx]=val;
}

static long query(int l,int r,int val)
{
long ret=0;

for(int i=idx[l]+1;i<idx[r];i++)
{
ret=ret+query(i,val+1);
}

for(int i=l;i<=Math.min(end[idx[l]],r);i++)
{
ret=ret+(arr[i]>val?1:0);
}

if(idx[l]!=idx[r])
{
for(int i=start[idx[r]];i<=r;i++)
{
ret=ret+(arr[i]>val?1:0);
}
}

return ret;
}

static void update(int idx1,int idx2,int val)
{
while(idx2>0)
{
bit[idx1][idx2]+=val;idx2-=idx2&-idx2;
}
}

static int query(int idx1,int idx2)
{
int ret=0;

while(idx2<maxn)
{
ret=ret+bit[idx1][idx2];idx2+=idx2&-idx2;
}

return ret;
}

public static void run() throws Exception
{
int n=sc.nextInt();

x=new int[n];y=new int[n];cnt=new int[n];

for(int i=1;i<n;i++)
{
x[i]=sc.nextInt()-1;y[i]=sc.nextInt()-1;

cnt[x[i]]++;cnt[y[i]]++;
}

al=new int[n][];

for(int i=0;i<n;i++)
{
al[i]=new int[cnt[i]];cnt[i]=0;
}

for(int i=1;i<n;i++)
{
int u=x[i],v=y[i];

al[u][cnt[u]++]=v;al[v][cnt[v]++]=u;
}

a=new Pair[n];c=new int[n];

for(int i=0;i<n;i++)
{
a[i]=new Pair(i,sc.nextInt(),-1);
}

for(int i=0;i<n;i++)
{
a[i].b=sc.nextInt();

c[i]=a[i].b;
}

shuffle(c);Arrays.sort(c);

for(int i=0;i<n;i++)
{
a[i].b=Arrays.binarySearch(c,a[i].b)+1;
}

tin=new int[n];tout=new int[n];arr=new int[n];dfs(0,-1);

start=new int[block];end=new int[block];idx=new int[n];bit=new int[block][maxn];

for(int i=0,j=0;i<n;i+=block,j++)
{
start[j]=i;end[j]=Math.min(n-1,i+block-1);

for(int k=start[j];k<=end[j];k++)
{
idx[k]=j;
}
}

Arrays.sort(a);int j=0;long res=0;

// out.println(Arrays.toString(tin)+" "+Arrays.toString(tout)+" "+Arrays.toString(arr));

for(int i=0;i<n;i++)
{
while(j<i && a[j].a>a[i].a)
{
update(tin[a[j].idx],a[j].b);j++;
}

long curr=query(tin[a[i].idx],tout[a[i].idx],a[i].b);

res=res+curr;

// out.println((a[i].idx+1)+" "+curr);
}

out.println(res);out.close();
}

private static class Pair implements Comparable<Pair>
{
int idx,a,b;

public Pair(int idx,int a,int b)
{
this.idx=idx;this.a=a;this.b=b;
}

public int compareTo(Pair x)
{
return -(Integer.compare(this.a,x.a));
}
}

public static void main(String[] args) throws Exception
{
new Thread(null,new Runnable(){
public void run()
{
try
{
new beautiful_nodes().run();
}
catch(Exception e)
{

}
}
},"1",1<<26).start();
}
}
class FastScanner
{
BufferedReader in;
StringTokenizer st;

public FastScanner(BufferedReader in) {
this.in = in;
}

public String nextToken() throws Exception {
while (st == null || !st.hasMoreTokens()) {
st = new StringTokenizer(in.readLine());
}
return st.nextToken();
}

public String next() throws Exception {
return nextToken().toString();
}

public int nextInt() throws Exception {
return Integer.parseInt(nextToken());
}

public long nextLong() throws Exception {
return Long.parseLong(nextToken());
}

public double nextDouble() throws Exception {
return Double.parseDouble(nextToken());
}
}
coding problems solutions

Post navigation

Previous post
Next post
  • Automating Image Format Conversion with Python: A Complete Guide
  • HackerRank Separate the Numbers solution
  • How AI Is Revolutionizing Personalized Learning in Schools
  • GTA 5 is the Game of the Year for 2024 and 2025
  • Hackerrank Day 5 loops 30 days of code solution
How to download udemy paid courses for free

Pages

  • About US
  • Contact US
  • Privacy Policy

Programing Practice

  • C Programs
  • java Programs

HackerRank Solutions

  • C
  • C++
  • Java
  • Python
  • Algorithm

Other

  • Leetcode Solutions
  • Interview Preparation

Programming Tutorials

  • DSA
  • C

CS Subjects

  • Digital Communication
  • Human Values
  • Internet Of Things
  • YouTube
  • LinkedIn
  • Facebook
  • Pinterest
  • Instagram
©2025 Programmingoneonone | WordPress Theme by SuperbThemes