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HackerEarth Beautiful Badges problem solution

YASH PAL, 31 July 202417 February 2026
In this HackerEarth Beautiful Badges Assignment problem solution Lucy has got the task to create badges for all students of the school. A badge is created by superimposing two squares. The bottom square should be of blue colour and top square should be of yellow colour. The squares must be rotated in such a way that the projection of the badge displays 8 distinguishable vertices.
 
Please help Lucy find out the maximum number of badges she can make with available n squares.
 
 
HackerEarth Beautiful Badges problem solution

 

 

HackerEarth Beautiful Badges problem solution.

#include <bits/stdc++.h>
using namespace std;

#define MOD 1000000007
#define pb(x) push_back(x)
#define mp(x,y) make_pair(x,y)
#define FF first
#define SS second
#define s(n) scanf("%d",&n)
#define sl(n) scanf("%lld",&n)
#define sf(n) scanf("%lf",&n)
#define ss(n) scanf("%s",n)
#define sc(n) {char temp[4]; ss(temp); n=temp[0];}
#define LINF (long long)1e18
#define EPS 1e-9
#define maX(a,b) ((a)>(b)?(a):(b))
#define miN(a,b) ((a)<(b)?(a):(b))
#define abS(x) ((x)<0?-(x):(x))

typedef long long ll;
typedef unsigned long long LL;
typedef pair<int,int> PII;
typedef pair<LL,LL> PLL;
typedef pair<int,PII> TRI;
typedef vector<int> VI;
typedef vector<LL> VL;
typedef vector<ll> vl;
typedef vector<PII> VII;
typedef vector<TRI> VT;

int N, m;
PII a[100005];
const int MAXN = 2005;
int cnt[MAXN], one_st;


const int INF = 1000000000;


struct edge {
int a, b, cap, flow;
};

int n, s, t, d[MAXN], ptr[MAXN], q[MAXN];
vector<edge> e;
vector<int> g[MAXN];

void add_edge (int a, int b, int cap) {
edge e1 = { a, b, cap, 0 };
edge e2 = { b, a, 0, 0 };
g[a].push_back ((int) e.size());
e.push_back (e1);
g[b].push_back ((int) e.size());
e.push_back (e2);
}

bool bfs() {
int qh=0, qt=0;
q[qt++] = s;
memset (d, -1, n * sizeof d[0]);
d[s] = 0;
while (qh < qt && d[t] == -1) {
int v = q[qh++];
for (size_t i=0; i<g[v].size(); ++i) {
int id = g[v][i],
to = e[id].b;
if (d[to] == -1 && e[id].flow < e[id].cap) {
q[qt++] = to;
d[to] = d[v] + 1;
}
}
}
return d[t] != -1;
}

int dfs (int v, int flow) {
if (!flow) return 0;
if (v == t) return flow;
for (; ptr[v]<(int)g[v].size(); ++ptr[v]) {
int id = g[v][ptr[v]],
to = e[id].b;
if (d[to] != d[v] + 1) continue;
int pushed = dfs (to, min (flow, e[id].cap - e[id].flow));
if (pushed) {
e[id].flow += pushed;
e[id^1].flow -= pushed;
return pushed;
}
}
return 0;
}

int dinic() {
int flow = 0;
for (;;) {
if (!bfs()) break;
memset (ptr, 0, n * sizeof ptr[0]);
while (int pushed = dfs (s, INF))
flow += pushed;
}
return flow;
}

void precompute() {
}
void read() {
s(N);
for (int i = 0; i < N; ++i) {
int c_i, d_i;
s(c_i), s(d_i);
a[i] = make_pair(c_i, d_i);
}
}
void preprocess() {
sort(a, a + N);
int cur = -1;
one_st = -1;
for (int i = 0; i < N; ++i) {
if(i == 0 or (a[i] != a[i - 1])) {
++cur;
cnt[cur] = 1;
}
else cnt[cur]++;
if(one_st == -1 and a[i].FF == 2) one_st = cur;
}
N = unique(a, a + N) - a;
}

void solve() {
n = N + 2;;
s = 0, t = N + 1;
for (int i = 0; i < N; ++i) {
if(i < one_st) add_edge(s, i + 1, cnt[i]);
else add_edge(i + 1, t, cnt[i]);
}
for (int i = 0; i < one_st; ++i) {
int mind = ceil(a[i].SS / sqrt(2.0));
int maxd = floor(a[i].SS * sqrt(2.0));
for (int j = one_st; j < N; ++j) {
assert(a[j].FF != a[i].FF);
if(a[j].SS <= maxd and a[j].SS >= mind)
add_edge(i + 1, j + 1, min(cnt[i], cnt[j]));
}
}
cout << dinic();
}
int main() {
precompute();
read();
preprocess();
solve();
return 0;
}
 
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