C++ program to search a number from list by sequential search

In this post, we will write a C++ program to search a number from a list by sequential search with practical program code example and compiled output.

C++ program to search a number from a list by sequential search.

#include<iostream>
#include<conio.h>

int main()
{
    system("cls");

    int n,i,a[10];
    int ch='n';

    std::cout<<"Enter any number you want to seach = ";
    std::cin>>n;

    for(i=0;i<=9;i++)
        a[i] = rand()%100;

    for(i=0;i<=9;i++)
    {
        if(n==a[i])
            ch = 'y';
    }

    if(ch == 'y')
        std::cout<<"The number is found"<<std::endl;
    else
        std::cout<<"The number is not found"<<std::endl;

    for(i=0;i<=9;i++)
        std::cout<<a[i]<<"t";

    getch();
    return 0;
}

Output

Enter any number you want to search = 56
The number is found
46      30      82      90      56      17      95      15      48      26

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