HackerRank Class 2 Find the Torsional Angle solution in python YASH PAL, 31 July 2024 In this class 2 find the torsional angle problem You are given four points A, B, C, and D in a 3-dimensional Cartesian coordinate system. You are required to print the angle between the plane made by the points A, B, C and B, C, D in degrees. Problem solution in Python 2 programming. import math class Point: """docstring for Point""" def __init__(self, x, y, z): # super(Point, self).__init__() self.x = x self.y = y self.z = z def minus(self, other): return Point(self.x - other.x, self.y - other.y, self.z - other.z) def cross(self, other): return Point( self.y * other.z - self.z * other.y , self.z * other.x - self.x * other.z , self.x * other.y - self.y * other.x) def dot(self, other): return self.x * other.x + self.y * other.y + self.z * other.z def abs(self): return math.sqrt(self.x * self.x + self.y * self.y + self.z * self.z) def str(self): return "(" + str(self.x) + ", " + str(self.y) + ", " + str(self.z) + ")" def get_Point(): lst = map(float, raw_input().strip().split()) return Point(lst[0], lst[1], lst[2]) a = get_Point() b = get_Point() c = get_Point() d = get_Point() ab = a.minus(b) bc = b.minus(c) cd = c.minus(d) x = ab.cross(bc) y = bc.cross(cd) v = x.dot(y) / (x.abs() * y.abs()) print "%.2f" % (math.acos(v) / math.acos(0) * 90,) Problem solution in Python 3 programming. class Points(object): def __init__(self, x, y, z): self.x=x self.y=y self.z=z def __sub__(self, no): return Points((self.x-no.x),(self.y-no.y),(self.z-no.z)) def dot(self, no): return (self.x*no.x)+(self.y*no.y)+(self.z*no.z) def cross(self, no): return Points((self.y*no.z-self.z*no.y),(self.z*no.x-self.x*no.z),(self.x*no.y-self.y*no.x)) def absolute(self): return pow((self.x ** 2 + self.y ** 2 + self.z ** 2), 0.5) Problem solution in pypy programming. class Points(object): def __init__(self, x, y, z): self.x=x self.y=y self.z=z def __sub__(self, other): return Points(self.x-other.x, self.y-other.y, self.z-other.z) def dot(self, other): return (self.x*other.x)+ (self.y*other.y )+ (self.z*other.z) def cross(self, other): return Points( self.y*other.z - self.z*other.y, self.z*other.x - self.x*other.z, self.x*other.y - self.y*other.x ) def absolute(self): return pow((self.x ** 2 + self.y ** 2 + self.z ** 2), 0.5) Problem solution in pypy3 programming. from math import acos, sqrt, degrees class Vector: def __init__(self, x=0, y=0, z=0): self.x = x self.y = y self.z = z def __sub__(self, other): return Vector(self.x - other.x, self.y - other.y, self.z - other.z) def __mul__(self, other): return self.x * other.x + self.y * other.y + self.z * other.z def __and__(self, other): return Vector(self.y * other.z - other.y * self.z, other.x * self.z - self.x * other.z, self.x * other.y - other.x * self.y) def __abs__(self): return sqrt(self * self) def read_vector(): return Vector(*[float(x) for x in input().split()]) A = read_vector() B = read_vector() C = read_vector() D = read_vector() X = (B - A) & (C - B) Y = (C - B) & (D - C) phi = degrees(acos((X * Y)/(abs(X) * abs(Y)))) print('{:0.2f}'.format(phi)) coding problems python