HackerRank Hard Disk Drives problem solution YASH PAL, 31 July 2024 In this HackerRank Hard Disk Drives problem solution, we have given the locations of n pairs of hard disk drivers of HDDs and the number of computers K. we need to place all K computers in such a way that the total length of wire needed to connect each pair of HDDs to computers is minimal. and then print the total length on a new line. Problem solution in Java. import java.io.*; import java.util.*; public class Solution { static class Pll { long fi; long se; Pll(long fi, long se) { this.fi = fi; this.se = se; } Pll() {} } static long[] xs; static int lowerBound(long[] arr, long key) { if (key <= arr[0]) { return 0; } if (key > arr[arr.length - 1]) { return 0; } int index = Arrays.binarySearch(arr, 0, arr.length, key); if (index < 0) { index = - index - 1; if (index < 0) { return 0; } } while (index > 0 && arr[index-1] == key) { index--; } return index; } static int allo; static long[] segFi; static long[] segSe; static int[] child0; static int[] child1; static long x; static long xx; static void insert(int r, int rt, long l, long h) { long m = l+h >> 1; segFi[r] =segFi[rt] + 1; segSe[r] = segSe[rt] + xx; if (l < h-1) { if (x < m) { child1[r] = child1[rt]; child0[r] = allo++; insert(child0[r], child0[rt], l, m); } else { child0[r] = child0[rt]; child1[r] = allo++; insert(child1[r], child1[rt], m, h); } } } static long[] prefix; static int[] root; static long query(int l, int h) { long r = prefix[2*h]-prefix[2*l]; int rt0 = root[2*l]; int rt1 = root[2*h]; int k = h-l; l = 0; h = xs.length; while (k != 0 && l < h-1) { int m = l+h >> 1; long t = segFi[child0[rt1]] - segFi[child0[rt0]]; if (k < t) { h = m; rt0 = child0[rt0]; rt1 = child0[rt1]; } else { k -= t; r -= (segSe[child0[rt1]] - segSe[child0[rt0]])*2; l = m; rt0 = child1[rt0]; rt1 = child1[rt1]; } } if (k != 0) { r -= segSe[rt1] / segFi[rt1]*k*2; } return r; } static long[] dp; static long[] dp0; static void conquer(int l, int h, int jl, long jh) { if (l >= h) return; int m = l+h >> 1; long opt = Long.MAX_VALUE; int optj = jl; for (int j = jl; j < Math.min(jh, m); j++) { if (dp[j] < Long.MAX_VALUE) { long t = dp[j] + query(j, m); if (t < opt) { opt = t; optj = j; } } } dp0[m] = opt; conquer(l, m, jl, optj+1); conquer(m+1, h, optj, jh); } static int N = 100000; static int LOGN = 63-Long.numberOfLeadingZeros(N-1)+1; static int V = 4*(LOGN+1); public static void main(String[] args) throws IOException { BufferedReader br = new BufferedReader(new InputStreamReader(System.in)); BufferedWriter bw = new BufferedWriter(new FileWriter(System.getenv("OUTPUT_PATH"))); StringTokenizer st = new StringTokenizer(br.readLine()); int n = Integer.parseInt(st.nextToken()); int k = Integer.parseInt(st.nextToken()); Pll[] a = new Pll[n]; xs = new long[2*n]; for (int i = 0; i < n; i++) { st = new StringTokenizer(br.readLine()); int fi = Integer.parseInt(st.nextToken()); int se = Integer.parseInt(st.nextToken()); a[i] = new Pll(fi, se); xs[2*i] = fi; xs[2*i+1] = se; } Arrays.sort(a, (u, v) -> { return (int)((u.fi + u.se) - (v.fi + v.se)); }); prefix = new long[2*n+1]; for (int i = 0; i < n; i++) { prefix[2*i+1] = prefix[2*i]+a[i].fi; prefix[2*i+2] = prefix[2*i+1]+a[i].se; } Arrays.sort(xs); segFi = new long[2*n*V]; segSe = new long[2*n*V]; child0 = new int[2*n*V]; child1 = new int[2*n*V]; root = new int[2*n+1]; allo = 1; for (int i = 0; i < n; i++) { root[2*i+1] = allo++; x = lowerBound(xs, a[i].fi); xx = a[i].fi; insert(root[2*i+1], root[2*i], 0, 2*n); root[2*i+2] = allo++; x = lowerBound(xs, a[i].se); xx = a[i].se; insert(root[2*i+2], root[2*i+1], 0, 2*n); } dp = new long[n+1]; dp0 = new long[n+1]; Arrays.fill(dp, Long.MAX_VALUE); dp[0] = 0; for (int i = 0; i < k; i++) { conquer(1, n+1, 0, n); System.arraycopy(dp0, 1, dp, 1, n); } bw.write(String.valueOf(dp[n])); bw.newLine(); bw.close(); br.close(); } } Problem solution in C++. #include <bits/stdc++.h> using namespace std; #define sz(x) ((int) (x).size()) #define forn(i,n) for (int i = 0; i < int(n); ++i) typedef long long ll; typedef long double ld; typedef pair<int, int> pii; const int inf = int(1e9) + int(1e5); const ll infl = ll(2e18) + ll(1e10); const int maxnk = 310004; ll dbuf[maxnk]; ll *d[maxnk]; vector<pii> coords; vector<pii> v; namespace Set { int t[maxnk * 2]; int base = 1; void init() { base = 1; while (base < sz(coords)) base *= 2; fill(t, t + 2 * base, 0); } void put(int v, int val) { v += base; t[v] = val; while (v > 1) { v /= 2; t[v] = t[v * 2] + t[v * 2 + 1]; } } int prev(int v) { v += base; while (true) { int u = v; v /= 2; if ((u & 1) && t[u] != t[v]) { v *= 2; break; } } while (v < base) { v *= 2; if (t[v + 1] > 0) ++v; } return v - base; } int next(int v) { v += base; while (true) { int u = v; v /= 2; if (!(u & 1) && t[u] != t[v]) { v = v * 2 + 1; break; } } while (v < base) { v *= 2; if (t[v] == 0) ++v; } return v - base; } } namespace T { int bl, br; int pos; ll f; void init(int id) { Set::init(); bl = id, br = id + 1; Set::put(v[id].first, 1); Set::put(v[id].second, 1); pos = v[id].second; f = coords[v[id].second].first - coords[v[id].first].first; } void move(int to) { f += (coords[to].first - coords[pos].first) * 2; pos = to; } void ins(int id) { int l = v[id].first; int r = v[id].second; Set::put(l, 1); Set::put(r, 1); f += abs(coords[r].first - coords[pos].first); f += abs(coords[l].first - coords[pos].first); if (pos < l) pos = Set::next(pos); else if (r < pos) move(Set::prev(pos)); } void del(int id) { int l = v[id].first; int r = v[id].second; if (pos <= l) pos = Set::prev(pos); else if (r <= pos) move(Set::next(pos)); Set::put(l, 0); Set::put(r, 0); f -= abs(coords[r].first - coords[pos].first); f -= abs(coords[l].first - coords[pos].first); } void moveBounds(int nl, int nr) { assert(nl < nr); while (br < nr) ins(br++); while (bl > nl) ins(--bl); while (br > nr) del(--br); while (bl < nl) del(bl++); assert(bl == nl && br == nr); } } int ck; void divideAndConquer(int l, int r, int pl, int pr) { assert(T::bl == pl && T::br == l); int mid = (l + r) / 2; int pm = pl; T::moveBounds(pm, mid); pair<ll, int> best{T::f + d[ck][pm], pm}; for (pm = pl + 1; pm < min(mid, pr); ++pm) { T::moveBounds(pm, mid); best = min(best, {T::f + d[ck][pm], pm}); } d[ck + 1][mid] = best.first, pm = best.second; if (mid + 1 < r) { T::moveBounds(pm, mid + 1); divideAndConquer(mid + 1, r, pm, pr); } T::moveBounds(pl, l); if (l < mid) divideAndConquer(l, mid, pl, pm + 1); } int main() { #ifdef LOCAL assert(freopen("test.in", "r", stdin)); #else #endif int n, k; cin >> n >> k; forn (i, k + 1) d[i] = dbuf + i * (n + 1); vector<pii> _v; forn (i, n) { int l, r; cin >> l >> r; if (l > r) swap(l, r); _v.emplace_back(l, r); } sort(_v.begin(), _v.end(), [](pii a, pii b) { return a.first + a.second < b.first + b.second; }); forn (i, n) { coords.emplace_back(_v[i].first, i * 2); coords.emplace_back(_v[i].second, i * 2 + 1); } sort(coords.begin(), coords.end()); v.resize(n); forn (i, n) { v[i].first = lower_bound(coords.begin(), coords.end(), pii{_v[i].first, i * 2}) - coords.begin(); v[i].second = lower_bound(coords.begin(), coords.end(), pii{_v[i].second, i * 2 + 1}) - coords.begin(); } forn (i, k + 1) fill(d[i], d[i] + n + 1, infl); d[0][0] = 0; forn (j, k) { T::init(0); ck = j; divideAndConquer(1, n + 1, 0, n); } cout << d[k][n] << 'n'; } algorithm coding problems