Skip to content
Programmingoneonone
Programmingoneonone
  • Home
  • CS Subjects
    • IoT – Internet of Things
    • Digital Communication
    • Human Values
  • Programming Tutorials
    • C Programming
    • Data structures and Algorithms
  • HackerRank Solutions
    • HackerRank Algorithms Solutions
    • HackerRank C problems solutions
    • HackerRank C++ problems solutions
    • HackerRank Java problems solutions
    • HackerRank Python problems solutions
Programmingoneonone

HackerEarth Minimum Cabs problem solution

YASH PAL, 31 July 2024
In this HackerEarth Minimum Cabs, problem solution Assume there are N persons and each person needs exactly one cab. For each person, you are given the start time and end time (both inclusive) during which that person will travel. Find the minimum number of cabs required.
HackerEarth Minimum Cabs problem solution

HackerEarth Minimum Cabs problem solution.

#include <bits/stdc++.h>

using namespace std;
const int MAX = 1500;
int A[MAX];

int main(int argc, char* argv[])
{
if(argc == 2 or argc == 3) freopen(argv[1], "r", stdin);
if(argc == 3) freopen(argv[2], "w", stdout);
ios::sync_with_stdio(false);
int n, hh1, hh2, mm1, mm2, smins, emins, ans;
cin >> n;
for (int i = 0; i < n; i++) {
cin >> hh1 >> mm1 >> hh2 >> mm2;
smins = hh1 * 60 + mm1;
emins = hh2 * 60 + mm2;
A[smins]++;
A[emins+1]--;
}
ans = A[0];
for (int i = 1; i < MAX; i++) {
A[i] += A[i-1];
ans = max(ans, A[i]);
}
cout << ans << endl;
return 0;
}
coding problems

Post navigation

Previous post
Next post
  • How AI Is Revolutionizing Personalized Learning in Schools
  • GTA 5 is the Game of the Year for 2024 and 2025
  • Hackerrank Day 5 loops 30 days of code solution
  • Hackerrank Day 6 Lets Review 30 days of code solution
  • Hackerrank Day 14 scope 30 days of code solution
©2025 Programmingoneonone | WordPress Theme by SuperbThemes