HackerRank XOR Strings 3 problem solution

def strings_xor(s, t):
    res = ""
    for i in range(len(s)):
        if s[i] == t[i]:
            res = res + '0' 
        else:
            res = res + '1'

    return res

s = input()
t = input()
print(strings_xor(s, t))

import java.io.*;
import java.util.*;
import java.text.*;
import java.math.*;
import java.util.regex.*;

public class Solution {

    public static String stringsXOR(String s, String t) {
        String res = new String("");
        for(int i = 0; i < s.length(); i++) {
            if(s.charAt(i) == t.charAt(i))
                res += "0";
            else
                res += "1";
        }

        return res;
    }

    public static void main(String[] args) {

        String s, t;
        Scanner in = new Scanner(System.in);
        s = in.nextLine();
        t = in.nextLine();
        System.out.println(stringsXOR(s, t));

    }

}

#include <cmath>
#include <cstdio>
#include <vector>
#include <iostream>
#include <algorithm>
using namespace std;

string strings_xor(string s, string t) {

    string res = "";
    for(int i = 0; i < s.size(); i++) {
        if(s[i] ^ t[i])
            res += '1';
        else
            res += '0';
    }

    return res;
}

int main() {
    string s, t;
    cin >> s >> t;
    cout << strings_xor(s, t) << endl;
    return 0;
}