HackerRank StringStream solution in c++ programming

In this HackerRank StringStream problem in the c++ programming language, In this challenge, we work with string streams.

stringstream is a stream class to operate on strings. It implements input/output operations on memory (string) based streams. stringstream can be helpful in different type of parsing. The following operators/functions are commonly used here

Operator >> Extracts formatted data.

Operator << Inserts formatted data.

Method str() Gets the contents of underlying string device object.

Method str(string) Sets the contents of underlying string device object.

Its header file is sstream.

One common use of this class is to parse comma-separated integers from a string (e.g., “23,4,56”).

stringstream ss(“23,4,56”);

char ch;

int a, b, c;

ss >> a >> ch >> b >> ch >> c;  // a = 23, b = 4, c = 56

Here ch is a storage area for the discarded commas.

If the >> operator returns a value, that is a true value for a conditional. Failure to return a value is false.

Given a string of comma delimited integers, return a vector of integers.

Function Description

Complete the parseInts function in the editor below.

parseInts has the following parameters:

• string str: a string of comma-separated integers

HackerRank StringStream problem solution in c++ programming.

#include <sstream>
#include <vector>
#include <iostream>
using namespace std;

vector<int> parseInts(string str) 
{
stringstream s(str);
vector <int> a;
char ch;
int t;
while(s>>t)
{ a.push_back(t);
s>>ch;}
return a;
}

int main() {
    string str;
    cin >> str;
    vector<int> integers = parseInts(str);
    for(int i = 0; i < integers.size(); i++) {
        cout << integers[i] << "n";
    }
    
    return 0;
}

Second solution

#include <sstream>
#include <vector>
#include <iostream>
using namespace std;

vector<int> parseInts(string str) {
    vector<int> res;
    bool read;
    stringstream ss(str);
    char ch;
    int i = 0, nextInt;
    
    while (1){
        if (i%2==0){
            read = (ss >> nextInt);
            if (!read) break;
            res.push_back(nextInt);
        }
        else{
            read = (ss >> ch);
        }
        i++;
    }
   return res;
}

int main() {
    string str;
    cin >> str;
    vector<int> integers = parseInts(str);
    for(int i = 0; i < integers.size(); i++) {
        cout << integers[i] << "n";
    }
    
    return 0;
}