Skip to content
Programmingoneonone
Programmingoneonone
  • CS Subjects
    • Internet of Things (IoT)
    • Digital Communication
    • Human Values
    • Cybersecurity
  • Programming Tutorials
    • C Programming
    • Data structures and Algorithms
    • 100+ Java Programs
    • 100+ C Programs
  • HackerRank Solutions
    • HackerRank Algorithms Solutions
    • HackerRank C problems solutions
    • HackerRank C++ problems solutions
    • HackerRank Java problems solutions
    • HackerRank Python problems solutions
  • Work with US
Programmingoneonone
Programmingoneonone

HackerRank Encryption problem solution

YASH PAL, 31 July 20241 December 2025

In this HackerRank Encryption problem solution, An English text needs to be encrypted using the following encryption scheme. First, the spaces are removed from the text. Let L be the length of this text. then, characters are written into a grid.

HackerRank Encryption problem solution

HackerRank Encryption problem solution in Python programming.

s = input()
n = 1
while n * n < len(s):
    n += 1

a = s + ' ' * (n * n - len(s))
a = [a[i:i+n] for i in range(0, n * n, n)]

print(' '.join([''.join([a[j][i] for j in range(n)]).strip() for i in range(n)]))

Encryption problem solution in Java Programming.

import java.io.*;
import java.util.*;

public class Solution {

    public static void main(String[] args) {
        /* Enter your code here. Read input from STDIN. Print output to STDOUT. Your class should be named Solution. */
        Scanner sc = new Scanner(System.in);
        String input = sc.next();
        int size = input.length();
        int rowSize = (int)Math.floor(Math.sqrt(size));
        int colSize = (int)Math.ceil(Math.sqrt(size));
       
        while(colSize>rowSize){
            colSize--;
            if((colSize*rowSize)<size){
                colSize++;
                break;
            }
        }
        while((colSize*rowSize)<size&&(colSize>rowSize)){
            rowSize++;
        }
        
        for(int i =0;i<colSize;i++){
            
            int row = 0;
            while(row<=rowSize-1){
                if((i+row*colSize)<size)
                {
                    System.out.print(input.charAt(i+row*colSize)); 
                     row++;
                }     else{
                    break;
                }        
             
            }
            System.out.print(" ");
        }
    }
}

Problem solution in C++ programming.

using namespace std;
#include <algorithm>
#include <iostream>
#include <iterator>
#include <sstream>
#include <fstream>
#include <cassert>
#include <climits>
#include <cstdlib>
#include <cstring>
#include <string>
#include <cstdio>
#include <vector>
#include <cmath>
#include <queue>
#include <deque>
#include <stack>
#include <map>
#include <set>

# define PI 3.14159265

int main()
{
              char msg[90];
              int row,col,i,j;
              scanf("%s",msg);
              int len=strlen(msg);   
              row=(int)sqrt(len);
              if((row*row)==len) col=row;
              else if(len<=(row*(row+1))) col=row+1;
              else
              {
                  row=row+1;col=row;
              }
              for(i=0;i<col;i++)
              {
                                for(j=i;j<len;j=j+col)
                                    printf("%c",msg[j]);
                                printf(" ");
              }
              printf("n");
              system("pause");     
              return 0;
}

Problem solution in C programming.

#include <stdio.h>
#include <string.h>
#include <math.h>

#define MAX_SIZE    82
#define MAX_ARRAY   10

char Input[MAX_SIZE];
char Output[MAX_ARRAY][MAX_ARRAY];

int main()
{
    int i, j, k;
    int Len;
    //int Width;
    int Height;
    //double Result;

    scanf("%sn", Input);
    //printf("%sn", Input);

    Len = strlen(Input);
    //printf("%dn", Len);

    //Result = sqrt(Len);

    //Width = floor(Result);
    Height = ceil(sqrt(Len));

    //printf("%d %dn", Width, Height);

    k = 0;
    for(i = 0; k < Len; ++i)
    {
        for(j = 0; ((j < Height) && (k < Len)); ++j, ++k)
        {
            Output[j][i] = Input[k];
        }
    }

    for(i = 0; i < (Height - 1); ++i)
    {
        printf("%s ", Output[i]);
    }
    printf("%sn", Output[i]);
}

Problem solution in JavaScript programming.

function processData(input) {
    var chars = input.split(''),
        w = Math.ceil(Math.sqrt(chars.length)),
        h = Math.ceil(Math.sqrt(chars.length)),
        result = [];
        
    for (var i = 0; i < h; i++) {
        var j = i, str = '';
        while (j < chars.length) {
            str += chars[j];
            j += w;
        }
        result.push(str);
    }
    
    console.log(result.join(' '));
} 

process.stdin.resume();
process.stdin.setEncoding("ascii");
_input = "";
process.stdin.on("data", function (input) {
    _input += input;
});

process.stdin.on("end", function () {
   processData(_input);
});

Algorithms coding problems solutions AlgorithmsHackerRank

Post navigation

Previous post
Next post

Leave a Reply

Your email address will not be published. Required fields are marked *

Pages

  • About US
  • Contact US
  • Privacy Policy

Follow US

  • YouTube
  • LinkedIn
  • Facebook
  • Pinterest
  • Instagram
©2026 Programmingoneonone | WordPress Theme by SuperbThemes