HackerRank Java Iterator problem solution YASH PAL, 31 July 2024 In this HackerRank Java Iterator problem in java programming, you need to complete a method func. The method takes an ArrayList as input. In that ArrayList there are one or more integer numbers, then there is a special string “###”, after that there are one or more other strings. You have to modify the func method by editing at most 2 lines so that the code only prints the elements after the special string “###”. F HackerRank Java Iterator problem solution. import java.util.*; public class Main { static Iterator func(ArrayList mylist) { Iterator it=mylist.iterator(); while(it.hasNext()) { Object element = it.next(); if(element instanceof String) break; } return it; } public static void main(String []argh) { ArrayList mylist = new ArrayList(); Scanner sc=new Scanner(System.in); int n=sc.nextInt(); int m=sc.nextInt(); for(int i=0;i<n;i++) { mylist.add(sc.nextInt()); } mylist.add("###"); for(int i=0;i<m;i++) { mylist.add(sc.next()); } Iterator it=func(mylist); while(it.hasNext()) { Object element = it.next(); System.out.println((String)element); } } } Second solution import java.util.*; public class Main{ static Iterator func(ArrayList mylist){ Iterator it=mylist.iterator(); while(it.hasNext()){ Object element = it.next(); if(element instanceof String) break; } return it; } @SuppressWarnings({ "unchecked" }) public static void main(String []args){ ArrayList mylist = new ArrayList(); Scanner sc = new Scanner(System.in); int n = sc.nextInt(); int m = sc.nextInt(); for(int i = 0;i<n;i++){ mylist.add(sc.nextInt()); } mylist.add("###"); for(int i=0;i<m;i++){ mylist.add(sc.next()); } Iterator it=func(mylist); while(it.hasNext()){ Object element = it.next(); System.out.println((String)element); } } } coding problems hackerrank solutions java